less hindered alkyl group should be provided by the alkyl halide and the more hin-
dered alkyl group should come from the alkoxide.
PROBLEM 21
What other organic product will be formed when the alkyl halide used in the synthesis of
butyl propyl ether is
a. propyl bromide?
b. butyl bromide?
PROBLEM 22
How could the following ethers be prepared, using an alkyl halide and an alcohol?
a. c.
b. d.
In Section 6.10, you saw that alkynes can be synthesized by the reaction of an
acetylide anion with an alkyl halide.
Now that you know that this is an reaction (the alkyl halide reacts with a high con-
centration of a good nucleophile), you can understand why it is best to use primary
alkyl halides and methyl halides in the reaction. These alkyl halides are the only ones
that form primarily the desired substitution product. A tertiary alkyl halide would form
only the elimination product, and a secondary alkyl halide would form mainly the
elimination product because the acetylide ion is a very strong base.
If you want to synthesize an alkene, you should choose the most hindered alkyl
halide in order to maximize the elimination product and minimize the substitution
product. For example, 2-bromopropane would be a better starting material than
1-bromopropane for the synthesis of propene because the secondary alkyl halide
would give a higher yield of the desired elimination product and a lower yield of the
competing substitution product. The percentage of alkene could be further increased
by using a sterically hindered base such as tert-butoxide ion instead of hydroxide ion.
2-bromopropane major product minor product
CH 3 CHCH 3 HO−
Br OH
+ CH 3 CH CH 2 ++CH 3 CHCH 3 H 2 O + Br−
1-bromopropane minor product major product
CH 3 CH 2 CH 2 Br + HO− CH 3 CH CH 2 +++CH 3 CH 2 CH 2 OH H 2 OBr−
SN 2
CH 3 CH 2 CC− + CH 3 CH 2 CH 2 Br CH 3 CH 2 C CCH 2 CH 2 CH 3 + Br−
CH 3 CH 2 OCH 2 CHCH 2 CH 2 CH 3
CH 3
OCCH 3
CH 3
CH 3
CH 3 CH 2 CHOCH 2 CH 2 CH 3 CH 2 O
CH 3
426 CHAPTER 11 Elimination Reactions of Alkyl Halides • Competition Between Substitution and Elimination
In synthesizing an ether, the less
hindered group should be provided
by the alkyl halide.
ethyl bromide
tert-butoxide ion tert-butyl ethyl ether
ethene
CH 3 CH 2 Br CH 3 CO−
CH 3
CH 3
CH 3 CH 2 OCCH 3
CH 3
CH 3
CH 3
CH 3
+ + CH 2 CH 2 ++CH 3 COH Br−
ethoxide ion
tert-butyl bromide
2-methylpropene
CH 3 CH 2 O− CH 3 CBr
CH 3
CH 3
CH 3
+ CH 2 CCH 3 ++CH 3 CH 2 OH Br−
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