To synthesize 2-methyl-2-butene from 2-bromo-2-methylbutane, you would use
conditions (a high concentration of in an aprotic polar solvent) because
a tertiary alkyl halide gives onlythe elimination product under those conditions. If
conditions were used (a low concentration of in water), both elimination
and substitution products would be obtained.
PROBLEM 23
Identify the three products that are formed when 2-bromo-2-methylpropane is dissolved in
a mixture of 80% ethanol and 20% water.
PROBLEM 24
a. What products (including stereoisomers if applicable) would be formed from the reac-
tion of 3-bromo-2-methylpentane with under conditions and under
conditions?
b. Answer the same question for 3-bromo-3-methylpentane.
11.10 Consecutive E2 Elimination Reactions
Alkyl dihalides can undergo two consecutive dehydrohalogenations, giving products
that contain two double bonds. In the following example, Zaitsev’s rule predicts the
most stable product of the first dehydrohalogenation, but not the most stable product
of the second. The reason Zaitsev’s rule fails in the second reaction is that a conjugat-
ed diene is more stable than an isolated diene.
If the two halogens are on the same carbon (geminal dihalides) or on adjacent car-
bons (vicinal dihalides), the two consecutive E2 dehydrohalogenations can result in
the formation of a triple bond. This is how alkynes are commonly synthesized.
−NH 2 −NH 2
a geminal dibromide a vinylic bromide
RCH 2 CR
Br
Br
Br
RCH CR ++2 NH 3 2 Br−
an alkyne
RC CR
−NH 2 −NH 2
a vicinal dichloride a vinylic chloride
RCHCHR
ClCl Cl
RCH CR ++2 NH 3 2 Br−
an alkyne
RC CR
SN 1 >E1
HO- SN 2 >E2
SN 1 >E1 HO-
SN 2 >E2 HO-
Section 11.10 Consecutive E2 Elimination Reactions 427
CH 3
2-bromo-2-methylbutane
2-methyl-2-butene
2-methyl-2-butanol
SN2/E2
conditions
SN1/E1
conditions
CH 3 CCH 2 CH 3 HO−
CH 3
Br
+
CH 3 C CHCH 3 + H 2 O + Br−
CH 3
CH 3 C
CH 3
OH
CHCH 3 + CH 3 CCH 2 CH 3 + H 2 O + Br−
HO− HO−
3,5-dichloro-2,6-dimethylheptane 5-chloro-2,6-dimethyl-2-heptene
CH 3 CHCHCH 2 CHCHCH 3
CH 3
Cl
CH 3
Cl
CH 3 CH 3
Cl
CH 3 C CHCH 2 CHCHCH 3
++2 H 2 O 2 Cl−
2,6-dimethyl-2,4-heptadiene
CH 3 CH 3
CH 3 C CHCH CHCHCH 3
BRUI11-400_436r3 26-03-2003 10:20 AM Page 427