Organic Chemistry

(Dana P.) #1
conversion of the alcohol to the ether via the alkyl tosylate involves only one
reaction: attack of on the alkyl tosylate. Therefore, the final product and the
starting material have opposite configurations.

PROBLEM 5

Show how 1-butanol can be converted into the following compounds:

a. d.

b. e.

c. f.

12.5 Elimination Reactions of Alcohols: Dehydration


An alcohol can undergo an elimination reaction, forming an alkene by losing an OH
from one carbon and an H from an adjacent carbon. Overall, this amounts to the elim-
ination of a molecule of water. Loss of water from a molecule is called dehydration.
Dehydration of an alcohol requires an acid catalyst and heat. Sulfuric acid
and phosphoric acid are the most commonly used acid catalysts.

An acid always reacts with an organic molecule in the same way: It protonates the
most basic (electron-rich) atom in the molecule. Thus, in the first step of the dehydra-
tion reaction, the acid protonates the oxygen atom of the alcohol. As we saw earlier,
protonation converts the very poor leaving group into a good leaving group
In the next step, water departs, leaving behind a carbocation. A base in the
reaction mixture (water is the base in highest concentration) removes a proton from a
-carbon (a carbon adjacent to the positively charged carbon), forming an alkene and
regenerating the acid catalyst. Notice that the dehydration reaction is an E1 reaction of
a protonated alcohol.

b

(H 2 O).

(-OH)

OH

CH 3 CH 2 CHCH 3 CH 3 CH CHCH 3 H 2 O


+

H 2 SO 4

(H 3 PO 4 )

(H 2 SO 4 )

CH 3 CH 2 CH 2 CH 2 OCH 3 CH 3 CH 2 CH 2 CH 2 C‚N

CH 3 CH 2 CH 2 CH 2 SH

O

CH 3 CH 2 CH 2 CH 2 OCCH 2 CH 3

CH 3 CH 2 CH 2 CH 2 Br CH 3 CH 2 CH 2 CH 2 NHCH 2 CH 3

CH 3 O-

SN 2

Section 12.5 Elimination Reactions of Alcohols: Dehydration 445

An acid protonates the most basic atom
in a molecule.

OH

CH 3 CHCH 3

OH
H

HOSO 3 H CH 3 CHCH 3 HCH 2 CHCH 3 CH 2 CHCH 3

−OSO
3 H

+

+

+

H 2 OH 3 O+

+

mechanism of dehydration (E1)

+ +

formation of
a carbocation

protonation of the
most basic atom

a base removes a
proton from a β-carbon

H

R OH

CH 3

H

Br R

CH 3

H

R OPBr 3

CH 3

H

R OCH 3

CH 3
PBr 3
pyridine

Br−

H

R OH

CH 3

H

CH 3 O R

CH 3

H

R OTs

CH 3
TsCl
pyridine

CH 3 O−

CH 3 O−

BRUI12-437_480r3 27-03-2003 11:51 AM Page 445

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