516 CHAPTER 13 Mass Spectrometry and Infrared Spectroscopy
2.5 2.6 2.72.82.9 3 3.5 4 4.5 5 5.5 6 7 8 9 10 11 12 13 14 15 16
4000 3800 3600 3400 3200 3000 2800 2600 2400 2200 2000 1800 1600 1400 1200 1000 800 600
Wavelength (μm)
Wavenumber (cm−^1 )
% Transmittance
O
CH 2 CCH 2 CH 3
Figure 13.33
The IR spectrum of Compound 5.
Summary
Mass spectrometryallows us to determine the molecular
massand the molecular formulaof a compound, as well as
certain structural features. In mass spectrometry, a small
sample of the compound is vaporized and then ionized as a
result of an electron’s being removed from each molecule,
producing a molecular ion—a radical cation. Many of the
molecular ions break apart into cations, radicals, neutral
molecules, and other radical cations. The bonds most like-
ly to break are the weakest ones and those that result in the
formation of the most stable products. The mass spectrom-
eter records a mass spectrum—a graph of the relative
abundance of each positively charged fragment, plotted
against its value.
The molecular ion (M) peak is due to the fragment that re-
sults when an electron is knocked out of a molecule; the m>z
m>z
value of a molecular ion gives the molecular mass of the
compound. The “nitrogen rule”states that if a compound has
an odd-mass molecular ion, the compound contains an odd
number of nitrogen atoms. Peaks with smaller values—
fragment ion peaks—represent positively charged frag-
ments of the molecule. The base peakis the peak with the
greatest intensity. High-resolution mass spectrometers deter-
mine the exact molecular mass, which allows a compound’s
molecular formula to be determined.
The peak occurs because there are two naturally
occurring isotopes of carbon. The number of carbon atoms in
a compound can be calculated from the relative intensities of
the M and peaks. A large peak is evidence of
a compound containing either chlorine or bromine; if it is
one-third the height of the M peak, the compound contains
M+ 1 M+ 2
M+ 1
m>z
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4000 3800 3600 3400 3200 3000 2800 2600 2400 2200 2000 1800 1600 1400 1200 1000 800 600
Wavelength (μm)
Wavenumber (cm−^1 )
% Transmittance
PROBLEM 29
A compound with molecular formula gives the infrared spectrum shown in
Figure 13.34. Identify the compound.
C 4 H 6 O
Figure 13.34
The IR spectrum for Problem 29.