Section 14.11 More Examples of^1 HNMR Spectra 549
ethylbenzene ( is a doublet, is a triplet, and is a doublet of doublets). The
nitro group is sufficiently electron withdrawing to cause the and protons to
be in different enough environments that their signals do not overlap.
Notice that the signals for the benzene ring protons in Figures 14.18 and 14.19
occur in the 7.0–8.5 ppm region. Other kinds of protons usually do not resonate in this
region, so signals in this region of an spectrum indicate that the compound
probably contains an aromatic ring.
PROBLEM 21
Explain why the signal for the protons identified as in Figure 14.19 appears at the
lowest frequency and the signal for the protons identified as appears at the highest
frequency. (Hint:Draw the contributing resonance structures.)
PROBLEM 22
How could spectra distinguish the following compounds?
PROBLEM 23
How would the spectra for the four compounds with molecular formula
differ?
PROBLEM 24
Identify each compound from its molecular formula and its 1 H NMRspectrum:
C 3 H 6 Br 2
1 H NMR
NO 2 NO 2 NO 2
Br
Br
Br
AB C
1 H NMR
Hc
Ha
1 H NMR
Ha, Hb, Hc
Hc Hb Ha
10 9 8765 4 3210
a.C 9 H 12
δ (ppm)
frequency
Tutorial:
NMR spectrum assignment