Section 2.2 Nomenclature of Alkanes 67
First, determine the number of carbons
in the longest continuous chain.
Number the chain so that the
substituent gets the lowest possible
number.
PROBLEM 2
Which of the following can be used to verify that carbon is tetrahedral?
a. Methyl bromide does not have constitutional isomers.
b. Tetrachloromethane does not have a dipole moment.
c. Dibromomethane does not have constitutional isomers.
PROBLEM 3
Write a structure for each of the following compounds:
a. isopropyl alcohol d. neopentyl chloride
b. isopentyl fluoride e.tert-butylamine
c.sec-butyl iodide f. n-octyl bromide
2.2 Nomenclature of Alkanes
The systematic name of an alkane is obtained using the following rules:
- Determine the number of carbons in the longest continuous carbon chain. This
chain is called the parent hydrocarbon. The name that indicates the number of
carbons in the parent hydrocarbon becomes the alkane’s “last name.”For exam-
ple, a parent hydrocarbon with eight carbons would be called octane. The
longest continuous chain is not always a straight chain; sometimes you have to
“turn a corner”to obtain the longest continuous chain. - The name of any alkyl substituent that hangs off the parent hydrocarbon is cited
before the name of the parent hydrocarbon, together with a number to designate
the carbon to which the alkyl substituent is attached. The chain is numbered in
the direction that gives the substituent as low a number as possible. The sub-
stituent’s name and the name of the parent hydrocarbon are joined in one word,
and there is a hyphen between the number and the substituent’s name.
CH 3 CHCH 2 CH 2 CH 3
CH 3
2-methylpentane 3-ethylhexane
4-isopropyloctane
1234 5
CH 3 CH 2 CH 2 CHCH 2 CH 3
CH 2 CH 3
654 321
CH 3 CH 2 CH 2 CHCH 2 CH 2 CH 2 CH 3
CHCH 3
CH 3
1234567 8
4-methyloctane 4-ethyloctane
4-propyloctane
CH 3 CH 2 CH 2 CH 2 CHCH 2 CH 2 CH 3
CH 3
three different alkanes with an
eight-carbon parent hydrocarbon
876543
321
21
CH 3 CH 2 CH 2 CH 2 CHCH 2 CH 3
CH 2 CH 2 CH 3
87654
CH 3 CH 2 CH 2 CHCH 2 CH 2 CH 3
CH 2 CH 2 CH 2 CH 3
4
56 78
32 1
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