688 CHAPTER 17 Carbonyl Compounds I
PROBLEM 10 SOLVEDa. Two amides are obtained from the reaction of acetyl chloride with a mixture of ethyl-
amine and propylamine. Identify the amides.
b. Only one amide is obtained from the reaction of acetyl chloride with a mixture of ethyl-
amine and pyridine. Why is only one amide obtained?SOLUTION TO 10a Either of the amines can react with acetyl chloride, so both
N-ethylacetamide and N-propylacetamide are formed.SOLUTION TO 10b Initially two amides are formed. However, the amide formed by
pyridine (a tertiary amine) is very reactive because it has a positively charged nitrogen atom,
which makes it an excellent leaving group. Therefore, it will react immediately with unre-
acted ethylamine, causing N-ethylacetamide to be the only amide formed in the reaction.PROBLEM 11Although excess amine is necessary in the reaction of an acyl chloride with an amine, ex-
plain why it is not necessary to use excess alcohol in the reaction of an acyl chloride with
an alcohol.PROBLEM 12Write the mechanism for the following reactions:a. the reaction of acetyl chloride with water to form acetic acid
b. the reaction of acetyl bromide with methylamine to form N-methylacetamidePROBLEM 13Starting with acetyl chloride, what nucleophile would you use to make each of the follow-
ing compounds?a. c. e.b. d. f. CH 3 COOCH 3 COH NO 2OCH 3 CNHCH 2 CH 3OCH 3 COCCH 3OOCH 3 CN(CH 3 ) 2OCH 3 COCH 2 CH 2 CH 3OCH 3 ClCH 3 CH 2 NH 2 CH 3 CH 2 CH 2 NH 2
NHCH 2 CH 3+ CH 3 CH 2 NH 3 Cl−+++
CH 3 CH 2 CH 2 NH 3 Cl−+CH 3 CH 3 NHCH 2 CH 2 CH 3
N-ethylacetamide N-propylacetamide++COCOCO−CH 3 ClCH 3 CH 2 NH 2
N++
CH 3 NHCH 2 CH 3+++
CH 3CH 3 CH 2 NH 2N+−−CH 3 CN
NH
CH 2 CH 3OHB B+
CH 3 CN
NH H
CH 2 CH 3O
CH 3 C NHCH 2 CH 3
N-ethylacetamideON N
HCl+ −HClCOCOCO+