Section 18.5 Reactions of Carbonyl Compounds with Hydride Ion 745The reaction is carried out at (the temperature of a dry ice–acetone bath). At
this cold temperature, the initially formed tetrahedral intermediate is stable, so it does
not eliminate the alkoxide ion. All of the unreacted hydride donor is removed from the
solution before the solution warms up. Therefore, when the tetrahedral intermediate
eliminates the alkoxide ion, there is no reducing agent to react with the aldehyde. If,
however, the reaction is carried out at room temperature, a primary alcohol is
obtained—the same product obtained when an ester reacts with
The reaction of a carboxylic acid with forms a single primary alcohol.
In the first step of the reaction, a hydride ion reacts with the acidic hydrogen of the
carboxylic acid, forming and a carboxylate ion. We have seen that nucleophiles do
not react with carboxylate ions because of their negative charge. However, in this case,
an electrophile is present that accepts a pair of electrons from the carboxylate
ion and forms a new hydride donor. Then, analogous to the reduction of an ester by
two successive additions of hydride ion take place, with an aldehyde being
formed as an intermediate on the way to the primary alcohol.
Acyl chlorides, like esters and carboxylic acids, undergo two successive additions
of hydride ion when treated with
Amides also undergo two successive additions of hydride ion when they react with
The product of the reaction is an amine. Primary, secondary, or tertiary
amines can be formed, depending on the number of substituents bonded to the nitrogen
LiAlH 4.
CO- LiAlH 4
CH 2. H^3 O+
3 CH 2 CH 2 Cl
CH 3 CH 2 CH 2 CH 2 OHbutanoyl chloride1-butanolLiAlH 4.LiAlH 4 ,
(AlH 3 )H 2acetic acidethanolbenzoic acid benzyl alcohol- LiAlH 4
CH 3 OH
CH 3 CH 2 OH- LiAlH 4
- H 3 O+
- H 3 O+
OHC CH 2 OHOCOLiAlH 4LiAlH 4.- 78 ° C
3-D Molecule:
Diisobutylaluminum hydride
H 3 O+O++a carboxylic acidmechanism for the reaction of a carboxylic acid with hydride ionan alcohol an aldehydeCH 3 COH H
+ H 2AlH 3AlH 3
OCH 3 COAlH 2O CH 3 CHO HH H
AlCH 3 COOO−CH 3 CH 2 OAlH 2 O−CH 3 CH 2 OH − CH 3 CHHAlH 3−−−−hydride ion
removes an
acidic protonnew hydride
donorsecond addition
of hydride ion