848 CHAPTER 20 More About Oxidation–Reduction ReactionsThe carbonyl group of an amide is reduced to a methylene group by lithium
aluminum hydride (Section 18.5). Primary, secondary, and tertiary amines are formed,
depending on the number of substituents bonded to the nitrogen of the amide. To obtain
the amine in its neutral basic form, acid is not used in the second step of the reaction.Because sodium borohydride cannot reduce an ester, an amide, or a carboxylic acid,
it can be used to selectively reduce an aldehyde or a ketone group in a compound that
also contains a less reactive group. Acid is not used in the second step of the following
reaction, in order to avoid hydrolyzing the ester:The multiply bonded carbon atoms of alkenes and alkynes do not possess a partial
positive charge and therefore will not react with reagents that reduce compounds by
donating a hydride ion.Because sodium borohydride cannot reduce carbon–carbon double bonds, a carbonyl
group in a compound that also has an alkene functional group can be selectively
reduced, as long as the double bonds are not conjugated (Section 18.13). Acid is not
used in the second step of the reaction, in order to avoid addition to the double bond.A chemoselective reactionis a reaction in which a reagent reacts with one func-
tional group in preference to another. For example, in isopropyl alcohol re-
duces aldehydes faster than it reduces ketones.O O OH OHNaBH 4
isopropyl alcoholNaBH 4CH 3 CHOHCHCH 2CH 3 CH CHCH 2 CHCH 3- NaBH 4
CH 2. H^2 O
3
COCH 3 CH 2 CH CH 2 no reduction reactionNaBH 4CH 3 CH 2 CCH no reduction reactionNaBH 4O OOCH 3OH OOCH 3- NaBH 4
- H 2 O
CH 3 CH 2 CH 2 CH 2 NHCH 3
a secondary amineCH 3 CH 2 CH 2 CH 2 NH 2- LiAlH 4
2. H 2 O
CH 3CH 3CH 3 CH 2 CH 2 CH 2 NCH 3
a tertiary amine- LiAlH 4
2. H 2 O - LiAlH 4
- H 2 O
CH 3 CH 2 CH 2 NH 2 a primary amine
CH 3 CH 2 CH 2 NHCH 3CH 3 CH 2 CH 2 NCH 3COCOCO(CH 2 )
Tutorial:
ReductionsBRUI20_841_882r3 01-04-2003 1:11 PM Page 848