If the leaving groups at C-2 and C-4 are different, the incoming nucleophile will
preferentially substitute for the weaker base (the better leaving group).
PROBLEM 19Compare the mechanisms of the following reactions:PROBLEM 20a. Propose a mechanism for the following reaction:b. What other product is formed?∆
N N O
HKOH/H 2 O+ −NH 2
NCl+ Cl−
NNH 2+ −NH 2Cl+ Cl−NH 2NBr−NH
2
OCH 3+
NNH 2Br−
OCH 3+∆NCH 3CH 3 O−
Cl+
NCH 3Cl−
OCH 3+∆−N2-positionmost stablemost stableN−− −−−− −−NN NN
NN N N4-position+ Y− 3-positionHYHYY HHYHYY HHYHYY H>Figure 21.3
Structures of the intermediates that
can be formed from the reaction of
a nucleophile with pyridine.Section 21.10 Aromatic Six-Membered-Ring Heterocycles 905Nucleophilic aromatic substitution of pyridine takes place at C-2 and C-4, because at-
tack at these positions leads to the most stable intermediate. Only when nucleophilic
attack occurs at these positions is a resonance contributor obtained that has the greatest
electron density on nitrogen, the most electronegative of the ring atoms (Figure 21.3).
slowmechanism for nucleophilic aromatic substitution
fast
Y−
N+
ZZ−
N+
N Z YY
−Pyridine undergoes nucleophilic
aromatic substitution at C-2 and C-4.Pyridine is lessreactive than benzene to-
ward electrophilic aromatic substitution
and morereactive than benzene toward
nucleophilic aromatic substitution.