Methods for Calculating Density
The density of wood (including water) at a given moisture
content, ρx, may be determined by any of three methods:
Method 1—Equations Using Basic Specific Gravity
The specific gravity Gx based on volume at the moisture
content of interest may be calculated from Equation (4–9)
or (4–11) with basic specific gravity taken from Table 5–3,
5–4, or 5–5 (Chap. 5). Density is then calculated by
(4–12)
Method 2—Equations Using Ovendry Density
Density is given by
( )
-
-
= +
x
x S
S
x
100
100
ρ ρ 01 / 100 0 (4–13)
where Sx is calculated using Equation (4–7) and S 0 is taken
from Table 4–3 or 4–4. If S 0 is not known for the particular
species of interest, it can be estimated using the same rela-
tion as in Equation (4–10), which in terms of ovendry
density is
(4–14)
Method 3—Using Figure 4–6 and Table 4–6
Figure 4–6 depicts the relationship between specific grav-
ity Gx and moisture content for different values of basic
specific gravity. This figure adjusts for average dimensional
changes that occur below the fiber saturation point (as-
sumed to be 30% MC) and incorporates the assumptions in
Equations (4–7), (4–10), and (4–11). The specific gravity of
wood does not change at moisture content values above ap-
proximately 30% because the volume does not change. To
use Figure 4–6, locate the inclined line corresponding to the
known basic specific gravity (volume when green). From
this point, move left parallel to the inclined lines until verti-
cally above the target moisture content. Then read the spe-
cific gravity Gx corresponding to this point at the left-hand
side of the graph.
For example, to estimate the density of white ash at 12%
moisture content, consult Table 5–3a in Chapter 5. The aver-
age basic specific gravity Gb for this species is 0.55 (volume
when green). Using Figure 4–6, the dashed curve for
Gb = 0.55 is found to intersect with the vertical 12%
moisture content dashed line at a point corresponding to
G 12 = 0.605. The density of wood (including water) at this
moisture content can then be obtained from Table 4–6 (these
values are based on Eq. (4–12)). By interpolation, the spe-
cific gravity of 0.605 corresponds to a density at 12% MC
of 678 kg m–3 (42.2 lb ft–3).
Thermal Properties
Four important thermal properties of wood are thermal con-
ductivity, heat capacity, thermal diffusivity, and coefficient
of thermal expansion.
Thermal Conductivity
Thermal conductivity k is a measure of the rate of heat flow
(W m–2 or Btu h–1 ft–2) through a material subjected to unit
temperature difference (K or °F) across unit thickness
(m or in.). The thermal conductivity of common structural
woods is much less than the conductivity of metals with
which wood often is mated in construction. It is about two
to four times that of common insulating materials. For ex-
ample, the conductivity of structural softwood lumber
at 12% moisture content is in the range of 0.10 to
0.14 W m–1 K–1 (0.7 to 1.0 Btu in. h–1 ft–2 °F–1) compared
with 216 (1,500) for aluminum, 45 (310) for steel, 0.9 (6)
for concrete, 1 (7) for glass, 0.7 (5) for plaster, and 0.036
(0.25) for mineral wool. Thermal resistivity is simply the
reciprocal of the thermal conductivity. Insulating materials
of a given thickness are commonly compared by their “R-
value,” or thermal resistance, which is simply the thermal
resistivity times the thickness.
The thermal conductivity of wood is affected by a number
of basic factors: density, moisture content, extractive con-
tent, grain direction, structural irregularities such as checks
0.1 8
0.2 2
0.2 6
0.3 0
0.3 4
0.3 8
0.4 2
0.4 6
0.5 0
0.5 4
0.5 8
0.6 2
0.6 6
0.7 0
0.7 4
0.7 8
0.8 2
0 2 4 6 8 10 12 14 16 18 20 22 24 26 28 30
0 .2 0
0 .2 4
0 .2 8
0 .3 2
0 .3 6
0 .4 0
0 .4 4
0 .4 8
0 .5 2
0 .5 6
0 .6 0
0 .6 4
(volume at current moisture content)
Specific gravity G
x
Moisture content (%)
Basic specific gravity Gb
(volume when green)
Figure 4–6. Relationship of specific gravity and
moisture content.
General Technical Report FPL–GTR– 190