CHEMICAL ENGINEERING

216 CHEMICAL ENGINEERING VOLUME 1 SOLUTIONS

From (v):
TwTg 20 Tw D 1. 741 TwTg 34. 82 Tg

∴ TwD 34. 82 Tg/
20 C 0. 741 Tg K(vi)

Substituting forTwfrom (vi) into (iv):

34. 82 Tg/

 27. 4 Tg 200 D 1. 46 Tg/

Tg 10 andTgD 11 .20 K

and hence, the temperature of the gas is
533  11. 2 D 521 .8K.