MASS TRANSFER 257
(b) For an age range of surface from 0 to 2/s, application of equation (ii) gives:
1 DK
∫ 2 /s
0
estdtDK
[
est
s
] 2 /s
0
D
K
s
1 e^2
or: KD
s
1 e^2
and: ft
D
s
1 e^2
est
ThusNAfrom equation (ii) is multiplied by factor 1/ 1 e^2 or:
NAD
1
1 e^2
p
DsCAD 1 .16 times the value in equation 3.
The mass transfer rate per unit total area of surface is:
NAD
∫ 2 /s
0
(√
D
t
CA
)
1. 16 sestdt
D
√
D
1. 16 sCA
∫ 2 /s
0
t^1 /^2 estdt
Putting: stDˇ^2
then: t^1 /^2 D
p
s
ˇ
and: sdtD 2 ˇdˇ
Integrating:
∫p 2
0
p
s
ˇ
eˇ
22 ˇ
s
dˇD
2
p
s
∫p 2
0
eˇ
2
dˇ
D
2
p
s
p
2
erf
p
2
D
√
s
erf
p
2
NAD
√
D
1. 16 s
√
s
CAerf
p
2 D 1. 16 ð 0. 954
p
DsCA
D 1. 107
p
DsCA
The mass transfer coefficient,hDD 1. 107
p
Ds, an increase of 10.7%
(c) For probability of surface renewal being linearly related to age,sDkt(wherekis a
constant)
Equation (i) becomes:
f^0 t
Cktft
D 0.
The integrating factor is: e
∫
ktdtDekt^2 / 2
ekt
(^2) / 2
ft
DK
and: ft
DKekt
(^2) / 2