MASS TRANSFER 279
Thus: CADCT 0. 25 0
D 0. 25 CT
CBmD1 0. 75
ln 0.^175CTD 0. 869 CT
CT
CBmD 1. 150
and the mass transfer rate:
ANA 0 D 0. 25 CT
17. 9 ð 10 ^6
L1. 150 AD 5. 15 ð 10 ^6ACT
L
kmol/sD 0 .090 kmol/sPROBLEM 10.45
What is the penetration theory for mass transfer across a phase boundary? Give details
of the underlying assumptions.
From the penetration theory, the mass transfer rate per unit areaNAis given in terms of
the concentration differenceCAbetween the interface and the bulk fluid, the molecular
diffusivityDand the agetof the surface element by:
NAD
√
D
tCA kmol/m^2 s (in SI units)What is the mean rate of transfer if all elements of the surface are exposed for the same
timetebefore being remixed with the bulk?
Danckwerts assumed a random surface renewal process in which the probability of
surface renewal is independent of its age. Ifsis the fraction of the total surface renewed
per unit time, obtain the age distribution function for the surface and show that the mean
mass transfer rateNAover the whole surface is:
NADp
DsCA kmol/m^2 s, in SI unitsIn a particular application, it is found that the older surface is renewed more rapidly than
the recently formed surface, and that after a times^1 , the surface renewal rate doubles,
that is it increases fromsto 2s. Obtain the new age distribution function.
Solution
Assuming the age spread of the surface ranges fortD0, totD1, consider the mass
transfer per unit area in each age group isttotCdtandsoon.
Then the mass transfer to surface in age groupttotCdtis:
D
√
D
CAt^1 /^2 dtThus the total mass transfer per unit area is:
√
D
CA
∫te0t^1 /^2 dtD√
D
CA
[
t^1 /^2
1
2]te0D 2
√
D
CAte^1 /^2