SECTION 4
Flow of Compressible Fluids
PROBLEM 4.1
A gas, having a molecular weight of 13 kg/kmol and a kinematic viscosity of 0.25 cm^2 /s,
flows through a pipe 0.25 m internal diameter and 5 km long at the rate of 0.4m^3 /s
and is delivered at atmospheric pressure. Calculate the pressure required to maintain this
rate of flow under isothermal conditions. The volume occupied by 1 kmol at 273 K and
101 .3kN/m^2 is 22.4m^3. What would be the effect on the required pressure if the gas
were to be delivered at a height of 150 m (i) above, and (ii) below its point of entry into
the pipe?
Solution
From equation 4.57 and, as a first approximation, omitting the kinetic energy term:
P 2 P 1 /vmC 4 R/u^2 l/dG/A^2 D 0
At atmospheric pressure and 289 K, the densityD 13 / 22. 4 273 / 289 D 0 .542 kg/m^3
Mass flowrate of gas,GD 0. 4 ð 0. 542 D 0 .217 kg/s.
Cross-sectional area,AD/ 4 0. 25 ^2 D 0 .0491 m^2.
Gas velocity,uD 0. 4 / 0. 0491 D 8 .146 m/s
∴ G/AD 0. 217 / 0. 0491 D 4 .413 kg/m^2 s
Reynolds number, ReDdu/
D 0. 25 ð 8. 146 / 0. 25 ð 10 ^4 D 8. 146 ð 104
From Fig. 3.7, fore/dD 0. 002 ,R/u^2 D 0. 0031
v 2 D 1 / 0. 542 D 1 .845 m^3 /kg
v 1 D 22. 4 / 13 298 / 273 101. 3 /P 1 D 190. 5 /P 1 m^3 /kg
and: vmD 0. 923 P 1 C 95. 25 /P 1 m^3 /kg
Substituting in equation 4.57:
P 1 P 1 101. 3 103 / 0. 923 P 1 C 95. 25 D 4 0. 0031 5000 / 0. 25 4. 726 ^2
and: P 1 D 111 .1kN/m^2
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