122 4. Particular Determinants
Theorem 4.36.
D(T
(n,r)
11
)=−(2n+r−1)T
(n,r+2)
n,n− 1
.
Proof.
T
(n,r)
11
=T
(n− 1 ,r+2)
.
The theorem follows by adjusting the parameters in Theorem 4.35.
Both these theorems are applied in Section 6.5.3 on the Milne–Thomson
equation.
4.9.3 Determinants with Simple Derivatives of All Orders
LetZrdenote the column vector with (n+ 1) elements defined as
Zr=
[
(^0) rφ 0 φ 1 φ 2 ···φn−r
]T
n+1
, 1 ≤r≤n, (4.9.15)
where 0rdenotes an unbroken sequence ofrzero elements andφmis an
Appell polynomial.
Let
B=
∣
∣Z
1 C 0 C 1 C 2 ···Cn− 1
∣
∣
n+1
, (4.9.16)
whereCjis defined in (4.9.5). DifferentiatingBrepeatedly, it is found that,
apart from a constant factor, only the first column changes:
D
r
(B)=(−1)
r
r!
∣
∣
Zr+1C 0 C 1 C 2 ···Cn− 1
∣
∣
n+1
, 0 ≤r≤n− 1.
Hence
D
n− 1
(B)=(−1)
n− 1
(n−1)!φ 0
∣
∣
C 0 C 1 C 2 ···Cn− 1
∣
∣
n
=(−1)
n− 1
(n−1)!φ 0 |φm|n, 0 ≤m≤ 2 n− 2
= constant;
that is,Bis a polynomial of degree (n−1) and not (n
2
−1), as may
be expected by examining the product of the elements in the secondary
diagonal ofB. Once again, the loss of degree due to cancellations isn(n−1).
Exercise
Let
Sm=
∑
r+s=m
φrφs.
This function appears in Exercise 2 at the end of Appendix A.4 on Appell
polynomials. Also, let
Cj=
[
Sj− 1 SjSj+1···Sj+n− 2
]T
n
, 1 ≤j≤n,
K=
[
- S 0 S 1 S 2 ···Sn− 2
]T
n
,
E=|Sm|n, 0 ≤m≤ 2 n− 2.