4.12 Hankelians 5 153
4.12 Hankelians 5
Notes in orthogonal and other polynomials are given in Appendices A.5 and
A.6. Hankelians whose elements are polynomials have been evaluated by a
variety of methods by Geronimus, Beckenbach et al., Lawden, Burchnall,
Seidel, Karlin and Szeg ̈o, Das, and others. Burchnall’s methods apply the
Appell equation but otherwise have little in common with the proof of the
first theorem in whichLm(x) is the simple Laguerre polynomial.
4.12.1 Orthogonal Polynomials
Theorem 4.54.
|Lm(x)|n=
(−1)
n(n−1)/ 2
0! 1! 2!···(n−2)!
n!(n+ 1)! (n+ 2)!···(2n−2)!
x
n(n−1)
,n≥ 2.
0 ≤m≤ 2 n− 2
Proof. Let
φm(x)=x
m
Lm
(
1
x
)
,
then
φ
′
m(x)=mφm− 1 (x),
φ 0 =1. (4.12.1)
Hence,φmis an Appell polynomial in which
φm(0) =
(−1)
m
m!
.
Applying Theorem 4.33 in Section 4.9.1 on Hankelians with Appell polyno-
mial elements and Theorem 4.47b in Section 4.11.3 on determinants with
binomial and factorial elements,
∣
∣
∣
∣
x
m
Lm
(
1
x
)∣
∣
∣
∣
n
=|φm(x)|n, 0 ≤m≤ 2 n− 2
=|φm(0)|n
=
∣
∣
∣
∣
(−1)
m
m!
∣ ∣ ∣ ∣ n =
∣
∣
∣
∣
1
m!
∣ ∣ ∣ ∣ n =
(−1)
n(n−1)/ 2
0! 1! 2!···(n−2)!
n!(n+ 1)! (n+ 2)!···(2n−2)!
. (4.12.2)
But
∣
∣
∣
∣
x
m
Lm
(
1
x
)∣
∣
∣
∣
n
=x
n(n−1)
∣
∣
∣
∣
Lm
(
1
x
)∣
∣
∣
∣
n