5.3 The Matsuno Identities 189
Hence,
An=xAn− 1.
ButA 2 =x
2
. The theorem follows.
5.3.2 Particular Identities..................
It is shown in the previous section thatAn=x
n
provided only that thexi
are distinct. It will now be shown that the diagonal elements ofAncan be
modified in such a way thatAn=x
n
as before, but only if thexiare the
zeros of certain orthogonal polynomials. These identities supplement those
given by Matsuno.
It is well known that the zeros of the Laguerre polynomialLn(x), the
Hermite polynomialHn(x), and the Legendre polynomialPn(x) are dis-
tinct. Letpn(x) represent any one of these polynomials and let its zeros be
denoted byxi,1≤i≤n. Then,
pn(x)=k
n
∏
r=1
(x−xr), (5.3.3)
wherekis a constant. Hence,
logpn(x) = logk+
n
∑
r=1
log(x−xr),
p
′
n
(x)
pn(x)
=
n
∑
r=1
1
x−xr
. (5.3.4)
It follows that
n
∑
r=1
r=i
1
x−xr
=
(x−xi)p
′
n
(x)−pn(x)
(x−xi)pn(x)
. (5.3.5)
Hence, applying the l’Hopital limit theorem twice,
n
∑
r=1
r=i
1
xi−xr
= lim
x→xi
[
(x−xi)p
′
n
(x)−pn(x)
(x−xi)pn(x)
]
= lim
x→xi
[
(x−xi)p
′′′
n(x)+p
′′
n(x)
(x−xi)p
′′
n
(x)+2p
′
n
(x)
]
=
p
′′
n
(xi)
2 p
′
n
(xi)
. (5.3.6)
The sum on the left appears in the diagonal elements ofAn. Now redefine
Anas follows:
An=|aij|n,