Determinants and Their Applications in Mathematical Physics

(Chris Devlin) #1
2.3 Elementary Formulas 9

Example.


C 1 C 3 C 4 C 2



=−



C 1 C 2 C 4 C 3



=



C 1 C 2 C 3 C 4



.

Applying this property repeatedly,

i.

∣C
mCm+1···CnC 1 C 2 ···Cm− 1


∣=(−1)(m−1)(n−1)A,

1 <m<n.

The columns in the determinant on the left are a cyclic permutation

of those inA.

ii.



CnCn− 1 Cn− 2 ···C 2 C 1



=(−1)

n(n−1)/ 2
A.

d.Any determinant which contains two or more identical columns is zero.




C 1 ···Cj···Cj···Cn



=0.

e. If every element in any one column ofAis multiplied by a scalarkand

the resulting determinant is denoted byB, thenB=kA.

B=



C 1 C 2 ···(kCj)···Cn



=kA.

Applying this property repeatedly,

|kaij|n=



(kC 1 )(kC 2 )(kC 3 )···(kCn)



=k

n
|aij|n.

This formula contrasts with the corresponding matrix formula, namely

[kaij]n=k[aij]n.

Other formulas of a similar nature include the following:

i.|(−1)

i+j
aij|n=|aij|n,

ii.|iaij|n=|jaij|n=n!|aij|n,

iii.|x

i+j−r
aij|n=x

n(n+1−r)
|aij|n.

f.Any determinant in which one column is a scalar multiple of another

column is zero.


C 1 ···Cj···(kCj)···Cn



=0.

g.If any one column of a determinant consists of a sum ofmsubcolumns,

then the determinant can be expressed as the sum ofmdeterminants,

each of which contains one of the subcolumns.





C 1 ···

(

m

s=1

Cjs

)

···Cn






=

m

s=1


∣C

1 ···Cjs···Cn


∣.

Applying this property repeatedly,





(

m

s=1

C 1 s

)

···

(

m

s=1

Cjs

)

···

(

m

s=1

Cns

)∣




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