34 3. Intermediate Determinant Theory
The result is:
AnBn=
∣
∣
∣
∣
∣
∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣
c 11 c 12 ... c 1 n
c 21 c 22 ... c 2 n
cn 1 cn 2 ... cnn
− 1 b 11 b 12 ... b 1 n
− 1 b 21 b 22 ... b 2 n
− 1 bn 1 bn 2 ... bnn
∣
∣
∣
∣
∣
∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣
2 n
. (3.3.17)
The product formula follows by means of a Laplace expansion.cijis most
easily remembered as a scalar product:
cij=
[
ai 1 ai 2 ···ain
]
•
b 1 j
b 2 j
···
bnj
. (3.3.18)
LetRidenote theith row ofAnand letCjdenote thejth column of
Bn. Then,
cij=Ri•Cj.
Hence
AnBn=|Ri•Cj|n
=
∣ ∣ ∣ ∣ ∣ ∣ ∣
R 1 • C 1 R 1 • C 2 ··· R 1 • Cn
R 2 • C 1 R 2 • C 2 ··· R 2 • Cn
······ ······ ··· ······
Rn•C 1 Rn•C 2 ··· Rn•Cn
∣ ∣ ∣ ∣ ∣ ∣ ∣ n
. (3.3.19)
Exercise.IfAn=|aij|n,Bn=|bij|n, andCn=|cij|n, prove that
AnBnCn=|dij|n,
where
dij=
n
∑
r=1
n
∑
s=1
airbrscsj.
A similar formula is valid for the product of three matrices.
3.4 Double-Sum Relations for Scaled Cofactors.........
The following four double-sum relations are labeled (A)–(D) for easy refer-
ence in later sections, especially Chapter 6 on mathematical physics, where
they are applied several times. The first two are formulas for the derivatives