4.3 Skew-Symmetric Determinants 65
=
∣
∣
∣
∣
Apr Aps
Aqr Aqs
∣
∣
∣
∣
+
∣
∣
∣
∣
Apq Aqs
Apr Ars
∣
∣
∣
∣
+
∣
∣
∣
∣
Aqr Ars
Apq Aps
∣
∣
∣
∣
=0.
The theorem follows immediately ifA= 0. However, since the identity is
purely algebraic, all the terms in the expansion ofSas sums of products
of elements must cancel out in pairs. The identity must therefore be valid
for all values of its elements, including those values for whichA= 0. The
theorem is clearly valid if the sum is carried out over even permutations of
any three of the four parameters.
Notes on skew-symmetric, circulant, centrosymmetric, skew-centrosym-
metric, persymmetric (Hankel) determinants, and symmetric Toeplitz
determinants are given under separate headings.
4.3 Skew-Symmetric Determinants................
4.3.1 Introduction
The determinantAn=|aij|nin whichaji=−aij, which impliesaii=0,
is said to be skew-symmetric. In detail,
An=
∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣
- a 12 a 13 a 14 ...
−a 12 • a 23 a 24 ...
−a 13 −a 23 • a 34 ...
−a 14 −a 24 −a 34 • ...
.............................
∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ n
. (4.3.1)
Theorem 4.8. The square of an arbitrary determinant of orderncan be
expressed as a symmetric determinant of ordernifnis odd or a skew-
symmetric determinant of ordernifnis even.
Proof. Let
A=|aij|n.
Reversing the order of the rows,
A=(−1)
N
|an+1−i,j|n,N=
[
n
2
]
. (4.3.2)
Transposing the elements of the original determinant across the secondary
diagonal and changing the signs of the elements in the new rows 2, 4 , 6 ,...,
A=(−1)
N
|(−1)
i+1
an+1−j,n+1−i|n. (4.3.3)
Hence, applying the formula for the product of two determinants in
Section 1.4,
A
2
=|an+1−i,j|n|(−1)
i+1
an+1−j,n+1−i|n