68 4. Particular Determinants
Proof. LetAn=|aij|nand letEn+1 andFn+1denote determinants
obtained by borderingAnin different ways:
En+1=
∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣
11 11···
−x • a 12 a 13 ···
−x −a 12 • a 23 ···
−x −a 13 −a 23 • ···
··· ··· ··· ··· ···
∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣
n+1
andFn+1is obtained by replacing the first column ofEn+1by the column
[
0 − 1 − 1 − 1 ···
]T
n+1
.
BothAnandFn+1are skew-symmetric. Then,
En+1=An+xFn+1.
Return toEn+1and perform the column operations
C
′
j=Cj−C^1 ,^2 ≤j≤n+1,
which reduces every element to zero except the first in the first row and
increases every other element in columns 2 to (n+1) byx. The result is
En+1=|aij+x|n.
Hence, applying Theorems 4.9 and 4.10,
|aij+x| 2 n=A 2 n+xF 2 n+1
=A 2 n,
|aij+x| 2 n− 1 =A 2 n− 1 +xF 2 n
=xF 2 n.
The theorem follows.
Corollary. The determinant
A=|aij| 2 n, where aij+aji=2x,
can be expressed as a skew-symmetric determinant of the same order.
Proof. The proof begins by expressingAin the form
A=
∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣
xa 12 a 13 a 14 ···
2 x−a 12 xa 23 a 24 ···
2 x−a 13 2 x−a 23 xa 34 ···
2 x−a 14 2 x−a 24 2 x−a 34 x ···
··· ··· ··· ··· ···
∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣
2 n
and is completed by subtractingxfrom each element.
Let
An=|aij|n,aji=−aij,