160 CHAPTER 5 Energy Methods
(a) Deriveaformulaforthecentraldeflectionofthebeam,duetoP,whensimplysupportedateachendofthe
span.
(b) Ifbothendsofthespanareencastré,determinethemagnitudeofthefixedendmoments.
Ans. 3 PL^3 / 128 EI,5PL/48(hogging).
P.5.5 ThetubularsteelpostshowninFig.P.5.5supportsaloadof250NatthefreeendC.Theoutsidediameterof
thetubeis100mm,andthewallthicknessis3mm.Neglectingtheweightofthetubefindthehorizontaldeflection
atC.Themodulusofelasticityis206000N/mm^2.
Ans. 53.3mm.
Fig. P.5.5
P.5.6 AsimplysupportedbeamABofspanLanduniformsectioncarriesadistributedloadofintensityvarying
fromzeroatAtow 0 /unitlengthatBaccordingtothelaw
w=
2 w 0 z
L
(
1 −
z
2 L
)
perunitlength.Ifthedeflectedshapeofthebeamisgivenapproximatelybytheexpression
v=a 1 sin
πz
L
+a 2 sin
2 πz
L
evaluatethecoefficientsa 1 anda 2 andfindthedeflectionofthebeamatmidspan.
Ans. a 1 = 2 w 0 L^4 (π^2 + 4 )/EIπ^7 ,a 2 =−w 0 L^4 / 16 EIπ^5 , 0.00918w 0 L^4 /EI.
P.5.7 Auniformsimplysupportedbeam,spanL,carriesadistributedloadingwhichvariesaccordingtoaparabolic
lawacrossthespan.Theloadintensityiszeroatbothendsofthebeamandw 0 atitsmidpoint.Theloadingisnormal
toaprincipalaxisofthebeamcrosssection,andtherelevantflexuralrigidityisEI.Assumingthatthedeflected
shapeofthebeamcanberepresentedbytheseries
v=
∑∞
i= 1
aisin
iπz
L
findthecoefficientsaiandthedeflectionatthemidspanofthebeamusingthefirsttermonlyintheaboveseries.
Ans. ai= 32 w 0 L^4 /EIπ^7 i^7 (iodd),w 0 L^4 /94.4EI.
P.5.8 FigureP.5.8showsaplanepin-jointedframeworkpinnedtoarigidfoundation.Allitsmembersaremade
ofthesamematerialandhaveequalcross-sectionalareaA,exceptmember12whichhasareaA
√
2.