36 CHAPTER 1 Basic Elasticity
thatthisstressisσx.TheninEqs.(1.58),σx=σcorσsandσy=σz=0;thetotalstraininthecopperand
steelisthen,respectively,
εc=
σc
Ec
+αc T (i)
εs=
σs
Es
+αs T (ii)
Thetotalstraininthecopperandsteelisthesame,sincetheirendsarerigidlyattachedtoeachother.
Therefore,fromcompatibilityofdisplacement,
σc
Ec
+αc T=
σs
Es
+αs T (iii)
Thereisnoexternalaxialloadappliedtothebarsothat
σcAc+σsAs= 0
thatis, σs=−
Ac
As
σc (iv)
SubstitutingforσsinEq.(iii)gives
σc
(
1
Ec
+
Ac
AsEs
)
= T(αs−αc)
fromwhich σc=
T(αs−αc)AsEsEc
AsEs+AcEc
(v)
Also,αc>σssothatσcisnegativeandthereforecompressive.NowsubstitutingforσcinEq.(iv),
σs=−
T(αs−αc)AcEsEc
AsEs+AcEc
(vi)
whichispositiveandthereforetensileaswouldbeexpectedbyaphysicalappreciationofthesituation.
Finally,theextensionofthecompoundbar,δ,isfoundbysubstitutingforσcinEq.(i)orforσsin
Eq.(ii).Then,
δ= TL
(
αcAcEc+αsAsEs
AsEs+AcEc
)
(vii)