36 CHAPTER 1 Basic Elasticity
thatthisstressisσx.TheninEqs.(1.58),σx=σcorσsandσy=σz=0;thetotalstraininthecopperand
steelisthen,respectively,
εc=σc
Ec+αc T (i)εs=
σs
Es+αs T (ii)Thetotalstraininthecopperandsteelisthesame,sincetheirendsarerigidlyattachedtoeachother.
Therefore,fromcompatibilityofdisplacement,
σc
Ec+αc T=σs
Es+αs T (iii)Thereisnoexternalaxialloadappliedtothebarsothat
σcAc+σsAs= 0thatis, σs=−Ac
Asσc (iv)SubstitutingforσsinEq.(iii)gives
σc(
1
Ec+
Ac
AsEs)
= T(αs−αc)fromwhich σc=T(αs−αc)AsEsEc
AsEs+AcEc(v)Also,αc>σssothatσcisnegativeandthereforecompressive.NowsubstitutingforσcinEq.(iv),
σs=−T(αs−αc)AcEsEc
AsEs+AcEc(vi)whichispositiveandthereforetensileaswouldbeexpectedbyaphysicalappreciationofthesituation.
Finally,theextensionofthecompoundbar,δ,isfoundbysubstitutingforσcinEq.(i)orforσsin
Eq.(ii).Then,
δ= TL(
αcAcEc+αsAsEs
AsEs+AcEc)
(vii)