Problems 521
fromwhich
s1,0=16.96mm
sothatapointofzerowarpingoccursinthewall12atadistanceof8.04mmfromthepoint2asbefore.
Intheweb23,letthepointofzerowarpingoccurats 2 =s2,0.Then
2 ×
1
2
× 25 × 25 − 2 ×
1
2
×8.04s2,0= 424
whichgivess2,0=25mm(i.e.,ontheaxisofsymmetry).Clearly,fromsymmetry,afurtherpointofzero
warpingoccursintheflange34atadistanceof8.04mmfromthepoint3.Thewarpingdistributionis
thenobtaineddirectlyusingEq.(17.20)inwhich
AR=AR,O−A′R
Problems..............................................................................................
P.17.1 Auniform,thin-walled,cantileverbeamofclosedrectangularcrosssectionhasthedimensionsshownin
Fig. P.17.1. The shear modulusGof the top and bottom covers of the beam is 18000N/mm^2 , while that of the
verticalwebsis26000N/mm^2.
Fig. P.17.1