120 Problems €4 Solutions on Thermodynamics d Statistical Mechanics
(d) Show that the heat capacity at constant volume of a Van der Waals
gas is a function of temperature alone (i.e., independent of V).
(MIT)
Solution:
= 0, we get
(a) As shown in Fig. 1.33, from (dp/dV)T=T, = 0 and (azp/dV2)r=r,
3a (Vc - b)3
T--
- v,4
so
a 8a
27b2’ ‘- 27bR
Vc = 3b,p, = - T--
(b) pcVciRTc = 318.
(c) In Fig. 1.33, the horizontal line CD is the modified isotherm. The
area of CAE is equal to that of EBD. The idea is that the common points,
i.e., C and D of the Van der Waals isotherm and the physical isotherm have
the same Gibbs free energy. Because of G = G(T,p), the equality of T’s
and p’s respectively will naturally cause the equality of G. In this way,
That is,
LE Vdp - Lc Vdp = /DB Vdp - LB Vdp, or AS~AE = ASEBD
For a Van der Waals gas, the equation of state gives
so that