136 Problems d Solutions on Thermodynamics d Statistical Mechanics
Solution:
Referring to Fig. 1.37, we regard the whole process as isobaric.
dS
Choose the entropy at TI as zero for the a-phase. Since T- = C,
dT
one has
S = C In T + const. : Sa = C, In , S, = S1 + C, In
The changes in chemical potential are
Since Ap' = Ap,, we have
= 1.60 x J/g.K
Therefore
= (C, - C.,)T:! In (g) - SIT2
= 23.7 J/g.
Sl
Fig. 1.37.