Thermodynamics 155
and so
The central temperature is
T --R 9P^2 +TS=372K.
- 6k
1157
Let H be the flow of heat per unit time per unit area normal to the
isothermal surface through a point P of the body. Assunze the experimental
fact
H=-kVT,
where T is the temperature and k is the coefficient of thermal conductivity.
Finally the thermal energy absorbed per unit volume is given by cpT, where
c is the specific heat and p is the density.
(a) Make an analogy between the thermal quantities HI k, T, c, p and
(b) Using the results of (a) find the heat conduction equation.
(c) A pipe of inner radius rl, outer radius r2 and constant thermal
conductivity k is maintained at an inner temperature TI and outer tem-
perature T2. For a length of pipe L find the rate the heat is lost and the
temperature between rl and r2 (steady state).
the corresponding quantities El J, V, p of steady currents.
(SVNY, Bufiulo)
Solution:
(a) By comparison with Ohm's law J = aE = -0 grad V(V is voltage)
and conservation law of charge dp/at = -V. J, we obtain the analogy
cpT u p;H J; grad T grad V; k tl u.
(b) By the above analogy and charge conservation law, we have
cp- = -grad. (-k grad T) = kV2T.
aT
at
Then the heat conduction equation is
aT k
___ -V2T = 0.
at pc