352 Problems d Solutioru on Therdpamica 6' Statistical Mechanics
Solution:
Let n(w)dw denote the number of photons in the angular frequency
interval w - w + dw. Consider the pressure exerted on the walls by such
photons in the volume element dV at (r, 6, p) (Fig. 2.34). The probability
that they collide with an area dA of the wall is dA.cos 6/4ar2, each collision
contributing an impulse 2k cos 6 perpendicular to dA. Therefore, we have
Fig. 2.34.
dp, = - df
dAdt
dA. cos 6
ndw dV. ' 2k cos 6
- 4rr2
dAdt
dw
4adt
= -2nkcos2 6 sin Odrdddp ,
- 4rr2
P= 1
dp, = 1 :kcdw = 1 *du 3.
r<cdt
uu
3 3v
Integrating we get p = - = -, where u is the energy density and U is
the total energy. From the thermodynamic equation
dU = TdS - pdV ,
and p = U/3V, we obtain dU = 3pdV + 3Vdp. Hence 4pdV + 3Vdp = TdS.
For an adiabatic process dS = 0, 4- + 3- = 0. Integrating we have
dV dp
VP
4
pv4I3 = const., 7 = ;.