Statistical Physics 399
through unit area perpendicular to the 2-direction in unit time is nG/4.
In a collision the momentum transfer in the y-direction is mAu,. Since a
collision occurs over a distance - 1, the molecular mean free path, for an
order of magnitude calculation we can take
au, av,
aY aY
Av, = Ay- - I-.
Thus the shearing force across the unit area or the viscous force is
nmCAv, 1 au,
4 dY
f= = -nmGl-.
Hence the coefficient of viscosity is
v=-- - md-~,
nmZl
4 40
where u is the molecular collision cross section. q is seen to be independent
of pressure at constant temperature.
2203
Consider a dilute gas whose molecules of mass m have mean velocity
of magnitude 5. Suppose that the average velocity in the x-direction u,
increases monotonically with z, so that u, = uz(z) with Iu,~ << 5 and all
gradients small. There are n molecules per unit volume and their mean free
path is 1 where 1 >> d (molecular diameter) and 1 << L (linear dimension of
enclosing vessel).
(a) The viscosity q is defined as the proportionality constant between
the velocity gradient and the stress in the 2-direction on an imaginary plane
whose normal points in the z-direction. Find an approximate expression
for q in terms of the parameters given.
(b) If the scattering of molecules is treated like that of hard spheres,
what is the temperature dependence of q? The pressure dependence? As-
sume a Maxwellian distribution in both cases.
(c) If the molecular scattering cross section u o( E&>, where E,, is
the center-of-mass energy of two colliding particles, what is the temperature
dependence of q? Again assume a Maxwellian distribution.
(d) Estimate q for air at atmospheric pressure (10 dyn/cm2) and room
(Princeton)
temperature. State clearly your assumptions.