Problems and Solutions on Thermodynamics and Statistical Mechanics

(Ann) #1
Thermodynamics 45

(b) For A -+ B, the increase of the internal energy is

AU = &',,AT = C,,PA(VB - VA)/R = 3W/2 = 1.5 x lo5 J.


2x'05[ 1 lo5 *:-A I
C
I I I
I I
II I I
0 1.0 1.5 2.0
v(m3)
Fig. 1.17.

(c) By the first law of thermodynamics, the heat absorbed during A +
B is W + AU = 2.5 x lo5 3.


(d) For B + C, the adiabatic process of an monatomic ideal gas sat-
isfies the equation


pV7 = const. , where 7 = C,/C, = 5/3.


Thus p~v; = pcv,' and pc = (vB/vc)7pB = 1.24 x lo5 N/rn2.
In the process of reversible adiabatic expansion, the change in entropy is
AS = 0. This is shown by the calculation in detail as follows:


TC VC
TB VB
TcV2-l
= nC, In =o.
~Bv2-l

AS = nC,, In - + nR In -


1050
A mole of an ideal gas undergoes a reversible isothermal expansion
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