671017.pdf

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q

a

R

Figure 1: Cavity expansion source induced by the uniform pressure
on the internal spherical surface.


a uniform pressure푞on the internal spherical surface with
radius푎.
The fields of stress and displacement induced by the
pressure are as follows:


휎푅=

푎^3 푞

푅^3

, (1)

휎휑=휎휃=−

푎^3 푞

2푅^3

, (2)

푢푅=

푎^3 푞

4퐺푅^2

, (3)

where the푅is the distance between the center and the
calculation point, the퐺is the shear modulus of the soil, and
the휎푅,휎휑,and휎휃refer to radial, hoop, and tangential stresses,
respectively. Due to the spherical symmetry, the shear stresses
are equal to zero, that is,휏푅휑=휏푅휃=휏휑휃.
Theexpansioncausedbythepiletipisusuallysimulated
as a spherical cavity expansion [ 19 , 20 ]. Hence, attention will
be paid to the solutions of a single cavity expansion adjacent
to a slope. As shown inFigure 2, the depth of the cavity below
the horizontal ground surface is denoted byℎ,andtheangle
between the slope and vertical direction is denoted by훽.
Unlike cavity expansion in an infinite medium, the analytical
solutions of cavity problem near a slope are currently only
possible in elastic materials. Accordingly, the soil is assumed
to be an isotropic, homogeneous, and linear elastic material,
and only small strains occur during the process of the
cavity expansion. For simplicity, the gravitational stresses are
ignored.


3. The Solution Method

3.1. The Expansion of a Spherical Cavity and Its Image in the
Half-Space.The theoretical solution for the expansion of a
single spherical cavity in a half-space has been presented by
Keer et al. [ 16 ],wherethefreesurfaceofthehalf-spaceis
horizontal (푧=0).Similarly,thesolutionscanalsobederived
whenthefreesurfaceisvertical(푟=0). Taking the vertical
surface as the plane of symmetry, another virtual spherical
cavity is put at the image point which is shown inFigure 3.
The coordinate of the calculation point푝is(푟,푧),and푡is the
horizontal distance between the center of spherical cavity and
the vertical free surface.푅 1 is the distance from the spherical


o

t

z

r

h

q

a

Expansion of
a spherical
cavity

Ground

Slope

Figure 2: Expansion of a spherical cavity near the sloping ground.

o 1 o o 2
R 1 R 2

tt

(^12)
p(r,z)
z
r
Cavity
expansion source
Free
surface
Image source
Figure 3: A cavity expansion source and its image.
cavity to point푝,and푅 2 is the distance from the image to
point푝.휑 1 and휑 2 are the angles from푟direction to푅 1 and
푅 2 ,respectively.
The stress and displacement components of the cavity
expansion in a cylindrical coordinate system can be written
as
휎푟=휎푅cos^2 휙+휎휙sin^2 휙−휏푅휙sin2휙, (4)
휎푧=휎푅sin^2 휙+휎휙cos^2 휙+휏푅휙sin2휙, (5)
휏푟푧=(휎푅−휎휙)sin휙cos휙+휏푅휙cos2휙, (6)
푢푟=푢푅cos휙, 푢푧=푢푅sin휙. (7)
By substituting ( 1 )to( 3 )into( 4 )to( 7 )andusingthe
principle of superposition, the stress and displacement of the
spherical cavity and its image in the cylindrical coordinate are
as follows:


휎푟=

푎^3 푞

2

[

3 (푡+푟)^2

푅^51


1

푅^31

+

3 (푟−푡)^2

푅^52


1

푅^32

], (8)

휎푧=

푎^3 푞

2

[

2

푅^31


3 (푡+푟)^2

푅^51

+

2

푅^32


3 (푟−푡)^2

푅^52

], (9)
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