671017.pdf

0

0

5

10

15

20

25

0 0.20.40. 6 0. 8 − 3 − 6 − 9 − 12

10.5D

u(mm) (mm)

z(

cm )

(a)푦 = −10.5퐷

0

0

5

10

15

20

25

00.511. 5 − 2 − 4 − 6 − 8 − 10

7D

u(mm) (mm)

z(

cm )

(b)푦=−7퐷, passing by slope shoulder

0

Test

FEM

0

5

10

15

20

00.511. 52 − 2 − 4 − 6 − 8

u(mm) (mm)

z(

cm )

3D

(c)푦=−3퐷

Figure 5: Displacement distribution comparison of numerical analysis and test results on different vertical sections.u: horizontal displace-
ment;v: vertical displacement;D:pilediameter.

0

0 10 20 30 40 50

g

− 10

− 8

− 6

− 4

− 2

x=0

y=−12cm

z = 20.3cm

Test

FEM

(mm)

Figure 6: Vertical displacement history of a typical point by numerical analysis and test results.v: vertical displacement;g:g-level.