0
5
10
15
20
25
30
35
00.01 0.02 0.03 0. 04
Displacem ent (m)
−0. 01
y(
m)
C PE8R-8-60
C P E 4-2-15
C P E 4-4-15
C P E 4-8-15
(a) Grid number being 15 along the wall
5
10
15
20
25
30
35
00.01 0.02 0. 03 0. 04
Displacem ent (m)
−0. 01
y(
m)
0
C PE8R-8-60
C P E 4-2-30
C P E 4-4-30
C P E 4-8-30
(b) Grid number being 30 along the wall
0
5
10
15
20
25
30
35
00.01 0.02 0.03 0. 04
Displacem ent (m)
−0. 01
y(
m)
C PE8R-8-60
C P E 4-2-60
C P E 4-4-60
C P E 4-8-60
(c) Grid number being 60 along the wall
Figure 8: Comparison of horizontal displacements.
interpolation points being 10, 30, 60, and 120. This shows that
themethodusedhereachievedagoodresultforthebending
moment.
2.2. Errors in Displacement and Bending Moment.We u s e d
several meshes to do the computation. Grids along the length
ofthebeamwere32,64,and128(inthe푥direction, see
Figure 1).Sectionalpartitionswere1,2,4,8,16,and32.Two
element types, CPS4 and the 8-node reduced-integration
element (CPS8R), were employed in the analysis. The results
are shown in Tables 1 , 2 ,and 3 and in Figures 4 and 5 ,where
the term푚×푛denotes that there are푚grids along the푦
direction and푛grids along the푥direction; B, C, D, and E are
positions for error calculation (seeFigure 1).