The History of Mathematics: A Brief Course

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312 10. EUCLIDEAN GEOMETRY


c


D

A Β

FIGURE 24. Diagonal and side of a square.

of incommensurables, is an attempt to bring into sharper focus the theorems already

proved and to test the underlying assumptions of a theory—to rigorize. Are these

kinds of activity complementary, opposed, or simply unrelated to each other?

10.10. Hippocrates' quadrature of a lune used the fact that the areas of circles

are proportional to the squares on their radii. Could Hippocrates have known this

fact? Could he have proved it?

10.11. Plato apparently refers to the famous 3-4-5 right triangle in the Republic,

546c. Proclus alludes to this passage in a discussion of right triangles with commen-

surable sides. We can formulate the recipes that Proclus attributes to Pythagoras

and Plato respectively as

(2n + l)^2 + (2n^2 + 2n)^2 = (2n^2 + 2n+ l)^2

and

(2n)^2 + (ç^2 - l)^2 = (ç^2 + l)^2.

Considering that Euclid's treatise is regarded as a compendium of Pythagorean

mathematics, why is this topic not discussed? In which book of the Elements

would it belong?

10.12. Proposition 14 of Book 2 of Euclid shows how to construct a square equal in

area to a rectangle. Since this construction is logically equivalent to constructing the

mean proportional between two line segments, why does Euclid wait until Book 6,

Proposition 13 to give the construction of the mean proportional?

10.13. Show that the problem of squaring the circle is equivalent to the problem of

squaring one segment of a circle when the central angle subtended by the segment

is known. (Knowing a central angle means having two line segments whose ratio is

the same as the ratio of the angle to a full revolution.)

10.14. Referring to Fig. 18, show that all the right triangles in the figure formed

by connecting B' with C, C with K, and K' with L are similar. Write down a

string of equal ratios (of their legs). Then add all the numerators and denominators

to deduce the equation

(BB' + <%"+·· + KK' + LM) : AM = A'Β : ΒΑ.
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