Example. A gas chromatographic method for the separation of a mixture of
cyclohexane, t-butanol and benzene on a 10 m capillary column gave the follow-
ing data:Parameter Cyclohexane t-Butanol Benzene
tR 3 m 20 s 3 m 30 s 3 m 45 s
Wb 8s 9s 11s
Wh/2 4.6 s 5.1 s 6.2 sCalculate (a) the plate numbers, using both plate number formulae, for each
solute, (b) the plate heights, and (c) the resolution between adjacent pairs of
solutes.(a) plate numbers N (^16)
2
N5.54
2
cyclohexane N (^16)
2
10 000 N5.54
2
10 473
t-butanol N (^16)
2
8711 N5.54
2
9393
benzene N (^16)
2
6694 N5.54
2
7296
(b) plate heights H
cyclohexane H = 1.0 mm H = 0.95 mm
t-butanol H= 1.15 mm H= 1.06 mm
benzene H= 1.49 mm H= 1.37 mm
(c) resolution RS
cyclohexane/t-butanol RS = 20/17 = 1.2
2 DtR
(W 1 W 2 )
2 DtR
(W 1 W 2 )
10 000
N225
6.2225
11210
5.1210
9200
4.6200
8tR
Wh/2tR
Wb128 Section D – Separation techniques
Concentration axistR, 1 tR, 2
DtRW 1 W 2Time axis
Fig. 5. Measurement of the resolution of two adjacent Gaussian peaks.