Engineering Mechanics

(^548) „„„„„ A Textbook of Engineering Mechanics ∴ Frequency of motion, 2 2 11 1 (^22) G ggh n tLhk == = ππ+ Example 26.16. A bo ...

Chapter 26 : Helical Springs and Pendulums „„„„„ 549 and length of equivalent simple pendulum (L), 22 0·559 0·45 0·45 h kkGG h = ...

(^550) „„„„„ A Textbook of Engineering Mechanics Resolving the forces horizontally and equating the same, T sin θ = mω^2 r ...(i ...

Chapter 26 : Helical Springs and Pendulums „„„„„ 551 Example 26.19. A conical pendulum 1·5 m long is revolving at 30 revolutions ...

(^552) „„„„„ A Textbook of Engineering Mechanics Define the term ‘length of equivalent simple pendulum’. Obtain an expression f ...

Chapter 27 : Collision of Elastic Bodies „„„„„ 553 553553 Contents Introduction. Phenomenon of Collision. Law of Conservation o ...

(^554) „„„„„ A Textbook of Engineering Mechanics be noted that a body, which rebounds to a greater height is said to be more ela ...

Chapter 27 : Collision of Elastic Bodies „„„„„ 555 27.5. COEFFICIENT OF RESTITUTION Fig. 27.1. Consider two bodies A and B havin ...

(^556) „„„„„ A Textbook of Engineering Mechanics v 1 = Final velocity of the first body and m 2 , u 2 , v 2 = Corresponding valu ...

Chapter 27 : Collision of Elastic Bodies „„„„„ 557 12 12 99 2or 2 77 MU U =+Mv Mv =+v v ...(i) We also know from the law of coll ...

(^558) „„„„„ A Textbook of Engineering Mechanics Example 27.4. Three perfectly elastic balls A, B and C of masses 2 kg, 4 kg and ...

Chapter 27 : Collision of Elastic Bodies „„„„„ 559 27.8. LOSS OF KINETIC ENERGY DURING COLLISION The kinetic energy may be broad ...

(^560) „„„„„ A Textbook of Engineering Mechanics ∴ Loss of kinetic energy, during impact EL = E 1 – E 2 ( 11 22 222 2) ( 11 2 2) ...

Chapter 27 : Collision of Elastic Bodies „„„„„ 561 Solution. Given : Initial velocity of second body (u 2 ) = 0 (because it is a ...

(^562) „„„„„ A Textbook of Engineering Mechanics Loss of kinetic energy during impact We know that loss of kinetic energy during ...

Chapter 27 : Collision of Elastic Bodies „„„„„ 563 27.9. INDIRECT IMPACT OF TWO BODIES If the two bodies, before impact, are not ...

(^564) „„„„„ A Textbook of Engineering Mechanics The Newton’s Law of Collision of Elastic Bodies, also holds good for indirect i ...

Chapter 27 : Collision of Elastic Bodies „„„„„ 565 We know from the law of collision of elastic bodies that v 2 cos θ 2 – v 1 co ...

(^566) „„„„„ A Textbook of Engineering Mechanics Notes.1.In such cases, we do not apply the principle of momentum (i.e., equatin ...

Chapter 27 : Collision of Elastic Bodies „„„„„ 567 and velocity with which the ball rebounds, vgh g==×= 2 1 2 0.81 0.9 2 gm/s .. ...