Engineering Mechanics

(^320) „„„„„ A Textbook of Engineering Mechanics
S. No. Member Magnitude of force in kN Nature of force
1 BL, IX 15,720 Compression
2 LM, WX 1,750 Compression
3 CM, HW 14,750 Compression
4 MN, VW 2,000 Tension
5 DP, GT 13,780 Compression
6 NO, UV 3,500 Compression
7 OP, TU 1,875 Tension
8 PQ, ST 1,685 Compression
9 EQ, FS 12,810 Compression
10 KL, KX 14,050 Tension
11 NK, VK 12,060 Tension
12 OR, RU 4,000 Tension
13 QR, RS 5,815 Tension
14 RK 8,080 Tension
EXERCISE 14.3

1. A truss shown in Fig. 14.55 is subjected to two point loads at B and F. Find the forces in all
   the members of the truss and tabulate the results.
   Ans. AB = 1.0 kN (Compression)
   BC= 2.25 kN (Compression)
   CD= 2.25 kN (Compression)
   DE= 3.0 kN (Compression)
   AF = 1.5 kN (Tension)
   BF = 1.25 kN (Tension)
   CF= 0
   DF= 3.75 kN (Tension)
   DF= 0


2. A truss is subjected to two point loads at A as shown in Fig. 14.56. Find by any method, the
   forces in all the members of the truss.
   Ans. AB = 20.0 kN (Compression)
   BC= 0
   AD= 10.0 kN (Compression)
   BD= 14.1 kN (Tension)
   BF = 14.1 kN (Compression)
   CF= 0
   DE= 10.0 kN (Compression)
   EF = 10.0 kN (Tension)
   DG= 0
   GE= 14.1 kN (Tension)
   EH= 14.1 kN (Compression)
   FH= 10.0 kN (Compression)
   GH= 10.0 kN (Tension)

Fig. 14.55.

1.5 kN

4kN

3m 3m

4m

A

BC

D

E

F

Fig. 14.56.

20 kN

10 kN

3m 3m

3m

3m

A B C

D E F

G H