(^542) A Textbook of Engineering Mechanics
Fig. 26.7. Compound pendulum
–20
- 86 400 6400
h
=
∴
20 6400
1·48 km
86 400
h
×
==Ans.
EXERCISE 26.2
- A weight of 100 N is attached to two springs of stiffness 400 N/m and 500 N/m connected
together vertically. Determine the period of oscillation of the weight. (Ans. 1.35 s) - A weight of 200 N is suspended from two springs arranged in parallel. Determine the
periodic time of the weight, if the spring constants are 800 N/m and 1000 N/m respectively.
Also determine angular velocity of the weight. (Ans. 0·67 s ; 9·38 rad/s) - A pendulum having 500 mm long string is carrying a bob of mass 100 gm. Find the time
period of the pendulum. (Ans. 1·42 s) - In a laboratory, a spiral spring of stiffness 1·5 N/mm is available. Find the magnitude of
the weight, which should be hung from the spring, so that it oscillates with a periodic
time of 1 second. (Ans. 407 N) - Find the number of seconds a clock would gain per day, if the acceleration due to gravity
is increased in the ratio of 900 : 901. (Ans. 48) - Calculate the number of beats lost per day by a seconds’s pendulum, when its string is
increased by 1/10 000th of its length. (Ans. – 4·32) - A simple pendulum gains 4 seconds per day. Determine the change in length of the
pendulum in order to correct the time. (Ans. – 0·092 mm) - A second’s pendulum is taken on a mountain 1200 metres high. Find the number of beats
it will lose or gain per day on the mountain. Take radius of the earth as 6400 km.
(Ans. – 16·2 beats) - A second’s pendulum loses 10 seconds per day at the bottom of a mine. Find the depth of
the mine. Take radius of the earth as 6400 km. (Ans. 740 m)
26.8. COMPOUND PENDULUM
A compound pendulum, in its simplest form, consists of a rigid body suspended vertically at
O and oscillating with a small amplitude under the action of the force of gravity. At some instant, let
the position of the rigid body be at its extreme position as shown
in Fig. 26.7.
Let m = mass of the pendulum
h = Distance between point of
suspension (O) and the
centre of gravity (G) of the
body.
A little consideration will show, that if the pendulum is
given a small angular displacement θ, then the moment of the
couple tending to restore the pendulum in the equilibrium position
OA
= mgh sin θ = mghθ ...(i)
...(Since θ is very small, therefore substituting sin θ = θ)