Chapter 35 : Hydrostatics 731
Total pressure on one face of the plate
Let θ = Inclination of the plate with the water surface
∴ sin θ =2–1 1
33=We know that area of the circular plate,A = ()^22 (3) 2.25 m^2
44dππ
==πand depth of centre of gravity from the water surface,
x =12
1.5 m
2+
=∴ Total pressure on one face of the plate,
P =wA x=× π×9.8 2.25 1.5 kN
= 103.9 kN Ans.Position of the centre of pressure
We know that moment of inertia of a circular plate, about its centre of gravity,IG=
()44 4(3)^81 m
64 64 64dππ π
==∴ Depth of centre of pressure from the water surface,h =2
281 1
sin 64 3
1.5
2.25 1.5IG x
Axπ ⎛⎞
×⎜⎟
θ ⎝⎠
+= +
π×= 1.54 m Ans.Example 35.11. A triangular plate of 1 m base and 1.5 m altitude is immersed in water. The
plane of the plate is inclined at 30º with water surface, while the base is parallel to and at a depth of
2 m from the water surface as shown in the figure given below.
Fig. 35.14.
Find the total pressure on the plate and the centre of pressure.
Solution. Given: Base of the plate (b) = 1 m; Altitude of the plate (h) = 1.5 m and inclination
of the plate with the water surface (θ) = 30º.
Total pressure on the plate
We know that area of the triangular plate,A=11.50.75 m 2
22bh ×
==Fig. 35.13.