rjj¼ry¼E0r
E0iy¼
n 2 cosh 1 n 1 cosh 2
n 1 cosh 2 þn 2 cosh 1ð 2 : 26 Þt?¼tx¼
E0t
E0ix¼
2n 1 cosh 1
n 1 cosh 1 þn 2 cosh 2ð 2 : 27 Þtjj¼ty¼
E0t
E0iy¼
2n 1 cosh 1
n 1 cosh 2 þn 2 cosh 1ð 2 : 28 ÞIf light is incident perpendicularly on the material interface, then the angles are
h 1 ¼h 2 ¼0. From Eqs. (2.25) and (2.26) it follows that the reflection coefficients
are
rxðh 1 ¼ 0 Þ¼ryðh 2 ¼ 0 Þ¼n 1 n 2
n 1 þn 2ð 2 : 29 ÞSimilarly, forθ 1 =θ 2 = 0, the transmission coefficients aretxðh 1 ¼ 0 Þ¼tyðh 2 ¼ 0 Þ¼2n 1
n 1 þn 2ð 2 : 30 ÞExample 2.8Consider the case when light traveling in air (nair= 1.00) is
incident perpendicularly on a smooth tissue sample that has a refractive index
ntissue= 1.35. What are the reflection and transmission coefficients?
Solution: From Eq. (2.29) with n 1 =nairand n 2 =ntissueit follows that the
reflection coefficient isry¼rx¼ðÞ 1 : 35 1 : 00 =ðÞ¼ 1 : 35 þ 1 : 00 0 : 149and from Eq. (2.30) the transmission coefficient istx¼ty¼ 21 ðÞ: 00 =ðÞ¼ 1 : 35 þ 1 : 00 0 : 851The change in sign of the reflection coefficient rxmeans that thefield of the
perpendicular component shifts by 180° upon reflection.Thefield amplitude ratios can be used to calculate thereflectanceR (the ratio of
the reflected to the incidentflux or power) and thetransmittanceT (the ratio of the
transmitted to the incidentflux or power). For linearly polarized light in which the
vibrational plane of the incident light is perpendicular to the interface plane, the
total reflectance and transmittance are
2.4 Reflection and Refraction 41