Systems Biology (Methods in Molecular Biology)

(Tina Sui) #1
We now consider each of the two solutions forr>0, and
examine their linear stability in the usual way. First, we add a
small perturbation:

x¼xþE:

Substituting this into the equation yields

dE
dt

¼ rx^2


 2 xEE^2 , ð 28 Þ

and since the term in brackets on the RHS is trivially zero,
therefore

dE
dt

¼ 2 xE,

which has the solution

EðtÞ¼Aexpð 2 xtÞ:

From this, we see that forx¼þ

ffiffiffi
r

p
|x|!0ast!1(linear
stability); forx¼

ffiffiffi
r

p
jxj!0ast!1(linear instability).
In a typical “bifurcation diagram,” therefore, the saddle
node bifurcation atr¼0 corresponds to the creation of two
new solution branches. One of these is linearly stable, the other
is linearly unstable.
Let’s do the same for the next
l transcritical:dx/dt¼rxx^2
l supercritical pitchfork super:dx/dt¼rxx^3
l subcritical pitchfork sub:dx/dt¼rx+x^3

and easily we find the relative stability and instability.


  1. Linear stability analysis for systems
    Consider the two-dimensional nonlinear system


x_¼fðx,yÞ,
y_¼gðx,yÞ,
ð 29 Þ

and suppose thatðx,yÞis a steady state (equilibrium point), i.e.,
fðx,yÞ¼0 andgðx,yÞ¼ 0 :Now let’s consider a small pertur-
bation from the steady stateðx,yÞ

x¼xþu,
y¼yþv,
ð 30 Þ

whereuandvare understood to be small asu1 andv1. It
is natural to ask whetheruandvare growing or decaying so
thatxandywill move away form the steady state or move
towards the steady states. If it moves away, it is called unstable
equilibrium point, if it moves towards the equilibrium point,

86 Rodolfo Guzzi et al.

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