2018-10-01_Physics_For_You

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∫dm=M()massofthebody


r
M
cm = ∫rdm

1


.


Note: If an object has symmetric uniform mass
distribution about x axis then y coordinate of COM is
zero and vice-versa

Centre of Mass of a Uniform Rod
Suppose a rod of mass M and length L is lying along the
x-axis with its one end at x = 0 and the other at x = L.
Mass per unit length of the rod = M/L
Hence, dm, (the mass of the element dx situated at

x = x is)=

M


L


dx

e coordinates of the element PQ are (x, 0, 0).
erefore, x-coordinate of COM of the rod will be


x

xdm

dm

x

M


L


dx

ML

xdx

L


L L
L
cm ==









==






0 0
0

1


2


()


e y-coordinate of COM is y


ydm
cm dm
==∫

0


Similarly, zcm = 0


i.e., the coordinates of COM of the rod are

L


2


,, 00.







^


Or it lies at the centre of the rod.


RIGID BODY
A rigid body is one whose geometric shape and size
remains unchanged under the action of any external
force. When a rigid body performs rotational motion,
the particles of the body move in circles. e centres
of these circles lie on a straight line called the axis of
rotation, which is xed and perpendicular to the planes
of circle.

Torque and Angular Momentum
Torque is the turning eect of a force. If a force acting
on a object has a tendency to rotate the body about an
axis, the force is said to exert a torque on the body. It is
a vector quantity. In vector form,
Torque, τ=×


rF
In magnitude, W = r F sinq.
Here q is the angle between 



rFand.
Torque has the same dimensions as that of work i.e.
[ML^2 T–2]. But work is a scalar quantity whereas torque
is a vector quantity.


By convention, anticlockwise moments are taken as
positive and clockwise moments are taken as negative.

Special Cases





(the rod will not rotate)

Ifqt= 0°, then = 0

O P

axis of rotation

r F

• (^) O P
If = 180°, then = 0
(the rod will not rotate)
qt
axis of rotationF
r






Ifq= 90°, thent=rF(maximum torque)

O P

axis of rotation F q= 90°

r

Note : Same force acting at the same point can produce
either anticlockwise or clockwise torque depending
upon the location of the axis of rotation as shown in
the gure.

A B

Axis of rotation

F
Anticlockwise torque

C

Axis of rotation

F
Clockwise torque

C

A B

Work Done by Torque
Work done, W = torque u angular displacement
= W × 'q

Power, P

dW
dt

d
dt

===τ

θ
τω
Angular momentum of a particle about a given axis is
the moment of linear momentum of the particle about
that axis. It is denoted by symbol


L.


Angular momentum

  


Lr=×p
In magnitude, L = rp sinq
where q is the angle between rpand.
Angular momentum is a vector quantity. Its SI unit is
kg m^2 s–1. Its dimensional formula is [ML^2 T–1].

Relationship between Torque and Angular
Momentum
Rate of change of angular momentum of a body is equal
to the external torque acting upon the body.


τext=

dL
dt
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