2018-10-01_Physics_For_You

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respect to the pass axis of P 1. A monochromatic
source S of unpolarised light of intensity I 0 is
kept in front of the polaroid sheet P 1 as shown
in the gure. Determine the intensities of light
as observed by the observers O 1 , O 2 and O 3 as
shown.

SOLUTIONS


  1. No, the speed of light in glass (i.e., v) depends upon
    the colour of light (i.e., O).


As P = c/v, v


c
=
μ

, where c is the speed of light in a
vacuum.
According to Cauchy's formula.
P = a + b/O^2 , where a and b are constant and their values
depend upon the nature of the substance.


us, v c
ab


=



  • /λ^2
    As Or > Ov, vv < vr i,e., violet component of white light
    travels slower than the red component.



  1. Because of total internal reections, the diver will
    not see anything above water. Instead, he would see the
    reection of something on the sides and/or bottom of
    the pool.

  2. Because of their smaller wavelength, microwaves
    are not bent by objects of normal dimensions. So they
    can be used to beam signal in a particular direction.

  3. As^1111110
    Ff 12 fFff


=+, =−= or F = f

(as f 1 = f and f 2 = –f )



  1. Only those waves can be polarised which are
    transverse in nature. us, light waves, which are
    transverse in nature, can be polarised whereas sound
    waves, which are longitudinal cannot be polarised.

  2. Given that focal length of convex lens, f 1 = + 25 cm and
    focal length of concave lens, f 2 = –20 cm
    Equivalent focal length,
    1111
    25


1


20


1


Ff 12 f 100

= +=+



=−


? F = –100 cm


Power of the combination, P
F


==

=−

11
1

1
()mm

D

e focal length of the combination= 1 m = 100 cm.


e system will be diverging in nature as the focal length
is negative.


  1. From mirror formula,^111
    vfu


=−


Now for a concave mirror, f < 0 and for an object is
placed on the le side of the mirror, the object distance
u < 0
? 2 f < u < f or^1
2

11


fuf

>>


or −<−<−

1


2


11


fuf

or^11
2

1111


fffuff

−<−<−^ or

1


2


1


0


fv

<<


is implies that v < 0 so that image is formed on le.
Also the above inequality implies
2 f > v
or |2f | < |v| [' 2 f and v are negative]
i.e., the real image is formed beyond 2f.


  1. (a) Microwaves are used in radar. Because of their
    small wavelengths, microwaves are not diracted or
    bent by objects of normal dimensions. So these waves
    can be used to beam signal in a particular direction.
    (b) X-rays are used to photograph internal parts of a
    body, X-rays have high penetrating power.
    (c) Infrared rays are used for taking photographs of the
    sky during night and foggy conditions. is is because
    these radiations are readily absorbed by water molecules
    present in most materials. Aer absorption they heat up
    the materials and their surroundings.

  2. (a) Gamma rays lie between 10–11 m-10–14 m.
    ese rays are used in radiotherapy to treat certain
    cancers and tumors.
    (b) Infrared waves lie between 10–4 m-10–6 m. ese
    waves are used in taking photographs during conditions
    of fog, smoke etc as these waves are scattered less than
    visible rays.

  3. Fringe width, β=Dλ
    d
    When D and d are kept xed, β
    β


λ
11 λ

=

or λ λβ

(^1) β
1 630 81
72
==×.
.
==^5103
72
708 75
.


. nm
11. (a) From Snell’s law, we have :


sin()
sin()

i
r


At A, i = 60°; P =^3
Now, sin()

sin()
r

i
=
μ
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