ΔE¼constant ð 1 : 40 Þ
The simplest example of energy conservation is Bernoulli’s equation where fluid
flowing through a pipe having different radius as depicted in Fig.1.7.
Bernoulli’s equationfor per unit volume for a given area is written as
Pressure energyþkinetic energyþpotential energy¼constant ð 1 : 41 Þ
Pþ mU^2
= 2 þmgh¼Pþ ρU^2
= 2 þρgh¼constant ð 1 : 42 Þ
Now, from Fig.1.7, at two different points with different cross-section areas,
Equation (1.42) can be written as
P 1 þ ρU^21
= 2 þρgh 1 ¼P 2 þ ρU^22
= 2 þρgh 2 ð 1 : 43 Þ
Important Concepts
- Stokes law: Friction and Drag on spherical particles
Frictional force due to viscosity, which is also known asStokes dragis given by
Fd¼ 6 ΠηrU ð 1 : 44 Þ
where,
Fdis stokes drag,ηis dynamic viscosity, r is hydrodynamic radius of the
spherical particle, U is the flow velocity around the particle. 6Πηr is together is
calleddrag coefficientζ.
A 1 >A 2 , r 1 > r 2 , P 1 < P 2 , U 1 < U 2
Q (Volumetric flow rate) = U.A; Q 1 = Q 2
A 2 , r 2 , h 2 , P 2 ,U 2
A 1 , r 1 , h 1 , P 1 ,U 1
Q 1
Q 2
Fig. 1.7 According to
conservation law,
volumetric flow rate in the
pipe sections depicted as
red circlesmust remain
same. However, channel
diameters, cross-section
areas, and flow velocities of
the highlighted sections
different. Thus, to satisfy
Q 1 ¼Q 2 , flow velocity of
the smaller diameter>the
flow velocity of higher
diameter
20 C.K. Dixit