Topology in Molecular Biology

(ff) #1
36 A. Vologodskii

second contour ifi>M. All elements of the Alexander matrix exceptakk,
akk+1andakiare zero. The nonzero elements of thekth row are defined as
follows:

(1)k≤M, M > 1


(a) Fori=kori=k+1
akk=− 1 ,akk+1= 1 independent of the type of crossing;
(b) Fori=k,i=k+1,i≤M
akk=1,akk+1=−s;aki=s−1 for type I crossing,
akk=−s, akk+1=1;aki=s−1 for type II crossing;
(c) Fori>M
akk=1,akk+1=−t;aki=s−1 for type I crossing,
akk=−t, akk+1=1;aki=s−1 for type II crossing;

(2)k=M=1;i>M
akk=1−t, aki=s−1 independent of the type of crossing;
(3)k>M;N>M+1


(a) Fori=kori=k+1
akk=− 1 ,akk+1= 1 independent of the type of underpass;
(b) Fori=k,i=k+1,i>M
akk=1,akk+1=−t;aki=t−1 for type I crossing,
akk=−t, akk+1=1;aki=t−1 for type II crossing;
(c) Fori≤M
akk=1,akk+1=−s;aki=t−1 for type I crossing,
akk=−s, akk+1=1;aki=t−1 for type II crossing.

(4)k=N;N=M+1,i≤M
akk=1−s, aki=t−1 independent of the type of crossing.


These relationships hold under conditions that fork=Mone makes the
substitution (k+1)→1 and fork=Nthe substitution (k+1)→M+1. It
is also assumed that there is at least one crossing in each contour formed by
generators from different contours – in other case the contours are certainly
unlinked.
Then one has to calculate a minorAkjof orderN−1 of the Alexander
matrix and divide it by (s−1) ifj ≤M and by (t−1) ifj>M.The
resultant expression is multiplied by (±t−ms−n)(mandnare integers), so
that the polynomial so obtained has no negative powers, and the positive
powers are minimal, and the term with the largest total exponent must be
positive. The polynomial ∆(s, t) defined in this manner is calledthe Alexander
polynomial for the link of two contours. It is an invariant – it is rigorously
proved in the knot theory that the Alexander polynomials ∆(s, t) coincide for
equivalent links. For unlinked contours ∆(s, t)=0.
It is usually sufficient to calculate ∆(s, t) = 0 for the majority of problems
related with circular DNA molecules. The analysis shows that ∆(s, t)=0is
a more powerful topological invariant than the Gauss integral (which equals
∆(s, t) = 0) [26]. It has different values for the simplest links and for unlinked
Free download pdf