get. There are some sources for custom
6-bladed, 140 percent DAR props, but that’s
truly the max. If you need still more blade
area, you have no choice but to increase
diameter.
Minimum Diameter and
Blade Area
What’s needed is an easy way to check blade
area and relate it to diameter using the DAR.
I’ve worked out a formula that will allow
a quick estimate of the minimum diameter
required for either displacement or planing
hulls.
Formula 1-1. Minimum Prop Diameter
as a Function of Blade Area
or
Where
hp =total brake horsepower for each
engine
kW =total flywheel power for each
engine
DAR =disc area ratio (or blade area
ratio); expressed as a decimal
kts =maximum speed in knots
DARs FOR REPRESENTATIVE PROPS:
2-Bladed Sailer = 0. 24
3-Bladed Standard = 0. 50
3-Bladed Wide Blade = 0. 70
4-Bladed Standard = 0. 70
4-Bladed Wide Blade = 0. 95
5-Bladed Standard = 0. 95
5-Bladed Extra-Wide Blade = 1. 20
These formulas make a few simplifying
assumptions, which apply quite well to most
average boats:
e =efficiency = 0 .55 for displacement
boats and 0.70 for planing boats
wf =wake factor = 0. 9
propeller depth =1 to 3 feet (30 to 90 cm)
below the waterline
Full engine power is used in these formu-
las, not shaft power. The reduction for
shaft losses has been incorporated into the
formulas.
Using this formula, it’s a quick job with a
pocket calculator to see if a given boat is in
the right ballpark for blade area.
Example: Say you have a 40-foot (12.2 m)
sportfisherman powered with twin 400 hp
(298 kW) diesels, and it has standard
3-bladed props, 24 inches (61 cm) in diame-
ter. The boat gets a top speed of 30 knots. You
would find.
or
In other words, the 24-inch (61 cm), 3-bladed
prop is too small in diameter to have ade-
quate blade area and is likely to cavitate.
Given enough clearance and the right
reduction gear, you could go to a 28-inch
(71 cm), 3-bladed wheel. A more practical
solution—in most instances—is to go to
more blades, a wide-blade-pattern propeller,
or both.
Trying a standard 4-blader gives
or
which is spot on.
PART ONE: DRIVETRAIN INSTALLATIONS
Min.Prop.Dia.,in.(Displacement Hulls)
1
=
225 hp
DAR kts kts
×
××
NOTE:kts× ktsis the same as kts^1.^5
Min.Prop.Dia.,in.(Planing Hulls)
160
=
× hhp
DAR ××kts kts
Min.Prop.Dia.,cm (Displacement Hulls)
1
=
0081 .5kW
DAR kts kts
×
××
Min.Prop.Dia.,cm (Planing Hulls)
1384. 2
=
kW
DAR kts kts
×
××
160 400 hp
0 .50 DAR 30 kts
27. 9 in.
30 kts
×
××
= Min.Prop.Dia.
1384. 2 298 kW
0 .50 DAR 30 kts
70. 8
30 kts
×
××
= ccm Min.Prop.Dia.
160 400 hp
0 .70 DAR 30 kts
23. 5 in.
30 kts
×
××
= Min.Prop.Dia.
1384. 2 298 kW
0 .70 DAR 30 kts
59 .9c
30 kts
×
××
= mmMin.Prop.Dia.
Formula 1-1.