394 Chapter 6 Laplace Transform
Next, the equations are made dimensionless by introducing new vari-
ables:
C ̄=C−Ca
A , x ̄=
Vx
D( 0 ),
̄t= V
(^2) t
D( 0 ).
The new problem is
∂
∂x ̄
(
D(x ̄)
D( 0 )
∂C ̄
∂x ̄
)
−∂
C ̄
∂x ̄=
∂C ̄
∂ ̄t,^0 < ̄x,^0 <
̄t,
C ̄( 0 ,t ̄)=sin(ω ̄t), 0 < ̄t,
C ̄(x ̄, 0 )= 0 , 0 < ̄x,
whereω= 2 πD( 0 )/V^2 tC.
BecauseD(x ̄)depends in a complicated way onx ̄,anumericalsolution
was used. To check the numerical solution, the authors wished to find an
analytical solution of the problem corresponding to constant diffusivity,
D(x ̄)=D( 0 ).Letube the solution of
∂^2 u
∂x ̄^2
=∂u
∂x ̄
+∂u
∂ ̄t
, 0 <x ̄, 0 < ̄t,
u
(
0 , ̄t
)
=sin
(
ω ̄t
)
, 0 < ̄t,
u( ̄x, 0 )= 0 , 0 < ̄x,
ubounded asx→∞.
Find the Laplace transform of the solution of this problem.
28.The authors of the paper mentioned in Exercise 27 were particularly in-
terested in the persistent part of the solution. Use the methods of Sec-
tion 6.4 to show that the persistent part of the solution is
u 1 =
1
2 i
(
f(iω)−f(−iω)
)
,
where
f(iω)=exp
((
1
2
−
√
1
4
+iω
)
x ̄+iω ̄t
)
.
29.Find the square root required in the foregoing expression by setting
√
1
4
+iω=α+iβ