328 7. THE REDUCED DISTANCE
may write formula (7.65) at smooth points off as
(7.96)
( V'V'f +Re- 2 ~g) (Y, Y) (f)
=-
2
~fo
7
y'TH(X,Y)dr+1
7
~IV'xY+Rc(Y)-; 7 Yl
2
dr.
EXERCISE 7.53. What does the trace of this equality say?
We have the following property of the reduced distance f.
LEMMA 7.54 (Reduced distance as r ---+ 0). Given V E TpM, let f1V :
[O, T] ---+ M be the £-geodesic with limT--70+ vr~; ( r) = v. Then
(7.97) T--70+ lim f ( /1V (f) , f) = IVl~(o) ·
PROOF. Since limT--70 vrdJ: ( r) = v and '"YVl[o,7] is a minimal £-geodesic
when f is small (see Lemma 7.29), we have
lim f('"Yv(r),r)
T-t0+
= lim \;: {7 Vf (R('"Yv(i),i)+ lddf1v (7)1
2
) di
T-t0+ 2y T lo T g('Y(i'),1')
= hm..^1 r,; 1T v r:::: T. -;::;^1 I v^12 g(O) dr -= I v^12 g(O) •
T-tO+ 2yr 0 r
D
We conclude this subsection with a few exercises concerning the reduced
distance f,.
EXERCISE 7.55 (£-triangle inequality). Show that for any path f1
[ri, r2]---+ M,
L (11 (r2), r2) - L (11 (r1), r1)
= 2y72f (11 (r2), r2) - 2y7if (11 (r1), r1)
1
72 I d
1
2
= £ (11) -
71
VT V'f - d~ dr.
REMARK 7.56. Given points (ih, f1) and (112, f2), we may define
J:d ( ( ii_i, f1) , ( i]2,T2)) = L(q 1 ,7 1 ) (c°fa, f2)
~inf{£ (11): f1 (fi) = if.i, i = 1, 2}.
Then the above formula implies
J:d ((p, 0), (q1, r1)) + J:d ((q1, r1), (q2, r2)) 2: J:d ((p, 0), (q2, r2)).
Equality holds if and only if for some minimal £-geodesic f1 : [ri, r 2 ] ---+ M
we have ~; = V'f along ')1, where f is defined with respect to the basepoint
(p, 0).