140 20. COMPACTNESS OF THE SPACE OF 11;-SOLUTIONS
Hence, by Theorem 20.1, which says ASCR (gk (0)) = oo if Mk is noncom-
pact, we have that the manifold Mk is compact for all k.
We claim there exists a constant Co < oo independent of k such that
(20.23)
that is, we have a uniform curvature bound for all of the rescaled metrics
9k (0).
If not, then there would exist a subsequence {(Mk,9k (t))} and a corre-
sponding sequence of points {Yk E Mk} such that
(20.24)
as k --+ oo. Note that since A k ::::; 1, this implies
d~k(o)(xk,Yk)--+ 0
as k --+ oo. (Already the reader may sense that this is counterintuitive; we
shall confirm this by rescaling and taking a limit to obtain a contradiction.)
We rescale about the maximum curvature points so as to define
(20.25)
Then R9k (z, 0) :S R9k (yk, 0) = 1 for all z E Mk and k EN. So by the trace
Harnack estimate, which implies that fftR9k 2 0, we have
R 9 k (z, t) ::::; 1
for all z E Mk, t::::; 0, and k EN.
On the other hand, it follows from (20.22), i.e., R 9 k(xk,O)
(20.24) that
R9k (xki 0) --+ 0.
1, and
Since we are assuming Case (a), we have R-tik (yk, O)d~k(o) (xk, Yk) :S 1 and
hence by (20.25) we have the uniform distance bound
(20.26) d~k(O) (xki Yk) :'S 1.
For each k, since (Mh;,gk (t)) has nonnegative curvature operator and
is A;-noncollapsed at all scales, we have .that (Mh;,gk (t)) has uniformly
bounded (independent of k, by our rescaling) nonnegative curvature operator
and is A;-noncollapsed at all scales. Hence we may apply Hamilton's Cheeger-
Gromov-type compactness theorem to get a subsequence {(Mh;, 9k(t), Yk)}
which converges to a complete limit solution
(M~, 900 (t), Yoo)
with bounded nonnegative curvature operator and such that Xk --+ x 00 for
some x 00 E M 00 • Here we used (20.26) and passed to a subsequence.